Integrand size = 25, antiderivative size = 89 \[ \int \frac {(g x)^m \left (1-a^2 x^2\right )^p}{1+a x} \, dx=\frac {(g x)^{1+m} \operatorname {Hypergeometric2F1}\left (\frac {1+m}{2},1-p,\frac {3+m}{2},a^2 x^2\right )}{g (1+m)}-\frac {a (g x)^{2+m} \operatorname {Hypergeometric2F1}\left (\frac {2+m}{2},1-p,\frac {4+m}{2},a^2 x^2\right )}{g^2 (2+m)} \]
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Time = 0.03 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {904, 83, 126, 371} \[ \int \frac {(g x)^m \left (1-a^2 x^2\right )^p}{1+a x} \, dx=\frac {(g x)^{m+1} \operatorname {Hypergeometric2F1}\left (\frac {m+1}{2},1-p,\frac {m+3}{2},a^2 x^2\right )}{g (m+1)}-\frac {a (g x)^{m+2} \operatorname {Hypergeometric2F1}\left (\frac {m+2}{2},1-p,\frac {m+4}{2},a^2 x^2\right )}{g^2 (m+2)} \]
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Rule 83
Rule 126
Rule 371
Rule 904
Rubi steps \begin{align*} \text {integral}& = \int (g x)^m (1-a x)^p (1+a x)^{-1+p} \, dx \\ & = -\frac {a \int (g x)^{1+m} (1-a x)^{-1+p} (1+a x)^{-1+p} \, dx}{g}+\int (g x)^m (1-a x)^{-1+p} (1+a x)^{-1+p} \, dx \\ & = -\frac {a \int (g x)^{1+m} \left (1-a^2 x^2\right )^{-1+p} \, dx}{g}+\int (g x)^m \left (1-a^2 x^2\right )^{-1+p} \, dx \\ & = \frac {(g x)^{1+m} \, _2F_1\left (\frac {1+m}{2},1-p;\frac {3+m}{2};a^2 x^2\right )}{g (1+m)}-\frac {a (g x)^{2+m} \, _2F_1\left (\frac {2+m}{2},1-p;\frac {4+m}{2};a^2 x^2\right )}{g^2 (2+m)} \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.87 \[ \int \frac {(g x)^m \left (1-a^2 x^2\right )^p}{1+a x} \, dx=x (g x)^m \left (-\frac {a x \operatorname {Hypergeometric2F1}\left (1+\frac {m}{2},1-p,2+\frac {m}{2},a^2 x^2\right )}{2+m}+\frac {\operatorname {Hypergeometric2F1}\left (\frac {1+m}{2},1-p,\frac {3+m}{2},a^2 x^2\right )}{1+m}\right ) \]
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\[\int \frac {\left (g x \right )^{m} \left (-a^{2} x^{2}+1\right )^{p}}{a x +1}d x\]
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\[ \int \frac {(g x)^m \left (1-a^2 x^2\right )^p}{1+a x} \, dx=\int { \frac {{\left (-a^{2} x^{2} + 1\right )}^{p} \left (g x\right )^{m}}{a x + 1} \,d x } \]
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Result contains complex when optimal does not.
Time = 4.56 (sec) , antiderivative size = 328, normalized size of antiderivative = 3.69 \[ \int \frac {(g x)^m \left (1-a^2 x^2\right )^p}{1+a x} \, dx=\frac {0^{p} a^{m} a^{- m - 1} g^{m} m x^{m} \Phi \left (\frac {1}{a^{2} x^{2}}, 1, \frac {m e^{i \pi }}{2}\right ) \Gamma \left (- \frac {m}{2}\right )}{4 \Gamma \left (1 - \frac {m}{2}\right )} - \frac {0^{p} a^{- m - 1} a^{m - 1} g^{m} m x^{m - 1} \Phi \left (\frac {1}{a^{2} x^{2}}, 1, \frac {1}{2} - \frac {m}{2}\right ) \Gamma \left (\frac {1}{2} - \frac {m}{2}\right )}{4 \Gamma \left (\frac {3}{2} - \frac {m}{2}\right )} + \frac {0^{p} a^{- m - 1} a^{m - 1} g^{m} x^{m - 1} \Phi \left (\frac {1}{a^{2} x^{2}}, 1, \frac {1}{2} - \frac {m}{2}\right ) \Gamma \left (\frac {1}{2} - \frac {m}{2}\right )}{4 \Gamma \left (\frac {3}{2} - \frac {m}{2}\right )} + \frac {a^{2 p - 2} g^{m} p x^{m + 2 p - 1} e^{i \pi p} \Gamma \left (p\right ) \Gamma \left (- \frac {m}{2} - p + \frac {1}{2}\right ) {{}_{2}F_{1}\left (\begin {matrix} 1 - p, - \frac {m}{2} - p + \frac {1}{2} \\ - \frac {m}{2} - p + \frac {3}{2} \end {matrix}\middle | {\frac {1}{a^{2} x^{2}}} \right )}}{2 \Gamma \left (p + 1\right ) \Gamma \left (- \frac {m}{2} - p + \frac {3}{2}\right )} - \frac {a^{2 p - 1} g^{m} p x^{m + 2 p} e^{i \pi p} \Gamma \left (p\right ) \Gamma \left (- \frac {m}{2} - p\right ) {{}_{2}F_{1}\left (\begin {matrix} 1 - p, - \frac {m}{2} - p \\ - \frac {m}{2} - p + 1 \end {matrix}\middle | {\frac {1}{a^{2} x^{2}}} \right )}}{2 \Gamma \left (p + 1\right ) \Gamma \left (- \frac {m}{2} - p + 1\right )} \]
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\[ \int \frac {(g x)^m \left (1-a^2 x^2\right )^p}{1+a x} \, dx=\int { \frac {{\left (-a^{2} x^{2} + 1\right )}^{p} \left (g x\right )^{m}}{a x + 1} \,d x } \]
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\[ \int \frac {(g x)^m \left (1-a^2 x^2\right )^p}{1+a x} \, dx=\int { \frac {{\left (-a^{2} x^{2} + 1\right )}^{p} \left (g x\right )^{m}}{a x + 1} \,d x } \]
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Timed out. \[ \int \frac {(g x)^m \left (1-a^2 x^2\right )^p}{1+a x} \, dx=\int \frac {{\left (g\,x\right )}^m\,{\left (1-a^2\,x^2\right )}^p}{a\,x+1} \,d x \]
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